每一分组的算法流程如下：第一分组需要将上面四个链接变量复制到另外四个变量中：A到a，B到b，C到c，D到d。从第二分组开始的变量为上一分组的运算结果，即A = a， B = b， C = c， D = d。主循环有四轮（MD4只有三轮），每轮循环都很相似。第一轮进行16次操作。每次操作对a、b、c和d中的其中三个作一次非线性函数运算，然后将所得结果加上第四个变量，文本的一个子分组和一个常数。再将所得结果向左环移一个不定的数，并加上a、b、c或d中之一。最后用该结果取代a、b、c或d中之一。以下是每次操作中用到的四个非线性函数（每轮一个）。F( X ,Y ,Z ) = ( X & Y ) | ( (~X) & Z )G( X ,Y ,Z ) = ( X & Z ) | ( Y & (~Z) )H( X ,Y ,Z ) =X ^ Y ^ ZI( X ,Y ,Z ) =Y ^ ( X | (~Z) )（&是与（And），|是或（Or），~是非（Not），^是异或（Xor））这四个函数的说明：如果X、Y和Z的对应位是独立和均匀的，那么结果的每一位也应是独立和均匀的。F是一个逐位运算的函数。即，如果X，那么Y，否则Z。函数H是逐位奇偶操作符。假设Mj表示消息的第j个子分组（从0到15），常数ti是4294967296*abs( sin(i) ）的整数部分，i 取值从1到64，单位是弧度。（4294967296=232）现定义：FF(a ,b ,c ,d ,Mj ,s ,ti ) 操作为 a = b + ( (a + F(b,c,d) + Mj + ti) << s)GG(a ,b ,c ,d ,Mj ,s ,ti ) 操作为 a = b + ( (a + G(b,c,d) + Mj + ti) << s)HH(a ,b ,c ,d ,Mj ,s ,ti) 操作为 a = b + ( (a + H(b,c,d) + Mj + ti) << s)II(a ,b ,c ,d ,Mj ,s ,ti) 操作为 a = b + ( (a + I(b,c,d) + Mj + ti) << s)注意：“<<”表示循环左移位，不是左移位。这四轮（共64步）是：第一轮FF(a ,b ,c ,d ,M0 ,7 ,0xd76aa478 )FF(d ,a ,b ,c ,M1 ,12 ,0xe8c7b756 )FF(c ,d ,a ,b ,M2 ,17 ,0x242070db )FF(b ,c ,d ,a ,M3 ,22 ,0xc1bdceee )FF(a ,b ,c ,d ,M4 ,7 ,0xf57c0faf )FF(d ,a ,b ,c ,M5 ,12 ,0x4787c62a )FF(c ,d ,a ,b ,M6 ,17 ,0xa8304613 )FF(b ,c ,d ,a ,M7 ,22 ,0xfd469501)FF(a ,b ,c ,d ,M8 ,7 ,0x698098d8 )FF(d ,a ,b ,c ,M9 ,12 ,0x8b44f7af )FF(c ,d ,a ,b ,M10 ,17 ,0xffff5bb1 )FF(b ,c ,d ,a ,M11 ,22 ,0x895cd7be )FF(a ,b ,c ,d ,M12 ,7 ,0x6b901122 )FF(d ,a ,b ,c ,M13 ,12 ,0xfd987193 )FF(c ,d ,a ,b ,M14 ,17 ,0xa679438e )FF(b ,c ,d ,a ,M15 ,22 ,0x49b40821 )第二轮GG(a ,b ,c ,d ,M1 ,5 ,0xf61e2562 )GG(d ,a ,b ,c ,M6 ,9 ,0xc040b340 )GG(c ,d ,a ,b ,M11 ,14 ,0x265e5a51 )GG(b ,c ,d ,a ,M0 ,20 ,0xe9b6c7aa )GG(a ,b ,c ,d ,M5 ,5 ,0xd62f105d )GG(d ,a ,b ,c ,M10 ,9 ,0x02441453 )GG(c ,d ,a ,b ,M15 ,14 ,0xd8a1e681 )GG(b ,c ,d ,a ,M4 ,20 ,0xe7d3fbc8 )GG(a ,b ,c ,d ,M9 ,5 ,0x21e1cde6 )GG(d ,a ,b ,c ,M14 ,9 ,0xc33707d6 )GG(c ,d ,a ,b ,M3 ,14 ,0xf4d50d87 )GG(b ,c ,d ,a ,M8 ,20 ,0x455a14ed )GG(a ,b ,c ,d ,M13 ,5 ,0xa9e3e905 )GG(d ,a ,b ,c ,M2 ,9 ,0xfcefa3f8 )GG(c ,d ,a ,b ,M7 ,14 ,0x676f02d9 )GG(b ,c ,d ,a ,M12 ,20 ,0x8d2a4c8a )第三轮HH(a ,b ,c ,d ,M5 ,4 ,0xfffa3942 )HH(d ,a ,b ,c ,M8 ,11 ,0x8771f681 )HH(c ,d ,a ,b ,M11 ,16 ,0x6d9d6122 )HH(b ,c ,d ,a ,M14 ,23 ,0xfde5380c )HH(a ,b ,c ,d ,M1 ,4 ,0xa4beea44 )HH(d ,a ,b ,c ,M4 ,11 ,0x4bdecfa9 )HH(c ,d ,a ,b ,M7 ,16 ,0xf6bb4b60 )HH(b ,c ,d ,a ,M10 ,23 ,0xbebfbc70 )HH(a ,b ,c ,d ,M13 ,4 ,0x289b7ec6 )HH(d ,a ,b ,c ,M0 ,11 ,0xeaa127fa )HH(c ,d ,a ,b ,M3 ,16 ,0xd4ef3085 )HH(b ,c ,d ,a ,M6 ,23 ,0x04881d05 )HH(a ,b ,c ,d ,M9 ,4 ,0xd9d4d039 )HH(d ,a ,b ,c ,M12 ,11 ,0xe6db99e5 )HH(c ,d ,a ,b ,M15 ,16 ,0x1fa27cf8 )HH(b ,c ,d ,a ,M2 ,23 ,0xc4ac5665 )第四轮II(a ,b ,c ,d ,M0 ,6 ,0xf4292244 )II(d ,a ,b ,c ,M7 ,10 ,0x432aff97 )II(c ,d ,a ,b ,M14 ,15 ,0xab9423a7 )II(b ,c ,d ,a ,M5 ,21 ,0xfc93a039 )II(a ,b ,c ,d ,M12 ,6 ,0x655b59c3 )II(d ,a ,b ,c ,M3 ,10 ,0x8f0ccc92 )II(c ,d ,a ,b ,M10 ,15 ,0xffeff47d )II(b ,c ,d ,a ,M1 ,21 ,0x85845dd1 )II(a ,b ,c ,d ,M8 ,6 ,0x6fa87e4f )II(d ,a ,b ,c ,M15 ,10 ,0xfe2ce6e0 )II(c ,d ,a ,b ,M6 ,15 ,0xa3014314 )II(b ,c ,d ,a ,M13 ,21 ,0x4e0811a1 )II(a ,b ,c ,d ,M4 ,6 ,0xf7537e82 )II(d ,a ,b ,c ,M11 ,10 ,0xbd3af235 )II(c ,d ,a ,b ,M2 ,15 ,0x2ad7d2bb )II(b ,c ,d ,a ,M9 ,21 ,0xeb86d391 )所有这些完成之后，将a、b、c、d分别在原来基础上再加上A、B、C、D。即a = a + A，b = b + B，c = c + C，d = d + D然后用下一分组数据继续运行以上算法。4. 输出最后的输出是a、b、c和d的级联。当你按照我上面所说的方法实现MD5算法以后，你可以用以下几个信息对你做出来的程序作一个简单的测试，看看程序有没有错误。MD5 ("") = d41d8cd98f00b204e9800998ecf8427eMD5 ("a") = 0cc175b9c0f1b6a831c399e269772661MD5 ("abc") = 900150983cd24fb0d6963f7d28e17f72MD5 ("message digest") = f96b697d7cb7938d525a2f31aaf161d0MD5 ("abcdefghijklmnopqrstuvwxyz") = c3fcd3d76192e4007dfb496cca67e13bMD5 ("ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz") =f29939a25efabaef3b87e2cbfe641315MD5 ("8a683566bcc7801226b3d8b0cf35fd97") =cf2cb5c89c5e5eeebef4a76becddfcfdMD5加密字符串实例现以字符串“jklmn”为例。该字符串在内存中表示为：6A 6B 6C 6D 6E（从左到右为低地址到高地址，后同），信息长度为40 bits， 即0x28。对其填充，填充至448位，即56字节。结果为：6A 6B 6C 6D 6E 80 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00剩下64位，即8字节填充填充前信息位长，按小端字节序填充剩下的8字节，结果为。6A 6B 6C 6D 6E 80 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 28 00 00 00 00 00 00 00（64字节，512 bits）初始化A、B、C、D四个变量。将这64字节填充后数据分成16个小组（程序中对应为16个数组），即：M0：6A 6B 6C 6D （这是内存中的顺序，按照小端字节序原则，对应数组M(0)的值为0x6D6C6B6A，下同）M1：6E 80 00 00M2：00 00 00 00.....M14：28 00 00 00M15：00 00 00 00经过“3. 分组数据处理”后，a、b、c、d值分别为0xD8523F60、0x837E0144、0x517726CA、0x1BB6E5FE在内存中为a：60 3F 52 D8b：44 01 7E 83c：CA 26 77 51d：FE E5 B6 1Ba、b、c、d按内存顺序输出即为最终结果：603F52D844017E83CA267751FEE5B61B。这就是字符串“jklmn”的MD5值。