求问个ListDensityPlot的坐标问题

RN=((-1 + 3 v^(2/3)) (1 - 3 v^(2/3) + 4 t v))/(2 (1-3 v^(2/3) + 2 t v)^2);
PV=Table[RN,{t, 0, 1.2, 0.01},{v, 0, 5, 0.01}];
ListDensityPlot[PV, PlotLegends->All,FrameLabel->{Style["V/\!\(\*SubscriptBox[\(V\),\(c\)]\)",Italic,Bold,FontSize->15],Style["T/\!\(\*SubscriptBox[\(T\),\(c\)]\)",Italic,Bold,FontSize -> 15]}]

RN = ((-1 + 3 v^(2/3)) (1 - 3 v^(2/3) +
4 t v))/(2 (1 - 3 v^(2/3) + 2 t v)^2);
PV = Flatten[
ParallelTable[{v, t, RN}, {t, 0, 1.2, 0.01}, {v, 0, 5, 0.01}], 1];
ListDensityPlot[PV, PlotLegends -> All,
FrameLabel -> {Style["V/\!\(\*SubscriptBox[\(V\),\(c\)]\)", Italic,
Bold, FontSize -> 15],
Style["T/\!\(\*SubscriptBox[\(T\),\(c\)]\)", Italic, Bold,
FontSize -> 15]}]

用 `DataRange -> {{0, 5}, {0, 1.2}}` 就行